in the given figure , side ca of∆abc has been produced to e. if ac=ad=bd;angle acd =46°and angle bae=x°. find the value of x.
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Step-by-step explanation:
Given : AC = AD = BD
Soln.:
In ∆ABC
AC = AD { Given }
then , Angle C = Angle D { Since the opposite sides are equal , the opposite angles are also equal }
Angle D = 46°
Now , Angle D + Angle DAC + Angle A = 180° { Property of a ∆ }
Then , Angle DAC = 180° - 92°
=> 88°
Now , Angle BDA = 180° - 46° = 134° { Linear pair }
Similarly , In ∆ABD
AD = BD { Given }
Let , Angle A = Angle B = y
So , y + y + Angle BDA = 180° { Property of a ∆ }
So , y = 46/2 = 23°
Hence ,
Angle X + Angle BAD + Angle DAC = 180° { Angles on a straight line }
So , Angle X = 180° -111°
=> 69°
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