in the given figure, sides AB and AC of AABC have been produced
to D and E respectively. If ZCBD = x° and ZBCE = yº such that
x > y, show that AB > AC.
B
xº
(180
ml
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Answer:
Step-by-step explanation:
ΔABC
x>y {multiply both side by -1}
-x < -y {add 180°}
180°-x < 180°-y
ABD & ACE is straight line
So, (180°-x)=∠ABC ; (180°-y)=∠ACB
∠ABC < ∠ACB
AC < AB
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