In the given figure, sides AB and DC of a cyclic quadrilateral are produced to meet at P and the sides
ADand BC are produced to meet at Q. Find (i) angle BAD, angle CQD
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Answer:
Angle BAD =55°
Step-by-step explanation:
In triangle DAP,
50° +75°+ A = 180°
A = 180°-125°= 55°
Therefore, angle BAD = 55°
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