in the given figure, sides BA and CB of triangle ABC are produced to point D and E respectively. if angle dac= 135° and angle abe = 110° find angle ACB
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Step-by-step explanation:
piyush5891:
where is the explanation
Answered by
42
We can find angle CBA
given angle EBA=110°
angleCBA= 180-110 ( linear pair)
=70°
given CAD =135°
so angleCAB=180-135(linear pair)
=45°
so angle ACB = 180-(70+45) (angle sum property of triangle)
=65°
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