Question

In the given figure,sides CB and BA of triangle ABC have been produced to D and E respectively. such that angle ABD =110° and angle CAE = 135°. then angle ACB=?​

Answer 1

Answer:

We can find angle CBA

given angle EBA=110°

angleCBA= 180-110 ( linear pair)

=70°

given CAD =135°

so angleCAB=180-135(linear pair)

=45°

so angle ACB = 180-(70+45) (angle sum property of triangle)

=65°

Step-by-step explanation:

Answer 2

Step-by-step explanation:

R.E.F image

By linear angle

property,

∠1+96=180

∘

⇒∠1=84

∘

Similarly ∠2+130

∘

=180

∘

⇒∠2=50

∘

Now as sum of angles in a

triangle =180

∘

,⇒∠1+∠2+∠3=180

⇒∠3=180−134=46

∘

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