Question

In the given figure sides QP and RP of ∆PQR are produced to point S and T respectively. If angle SPR=135 degree and any PQT = 110 degree , find angle PQR.​

Answer 1

Answer:

ANSWER

∠PQT+∠PQR=180

∘

(Straight angle made on line TR at point Q)

110

∘

+∠PQR=180

∘

∠PQR=180

∘

−110

∘

=70

∘

In △PQR

∠PSR=∠PQR+∠PRQ (Exterior angle of triangle is eqal to sum of two interior angles)

135

∘

=70

∘

+∠PRQ

∠PRQ=135

∘

−70

∘

=65

∘

Answer 2

Answer:

your answer........

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