Question

In the given figure, straight lines AB and CD intersect at 0. If _AOC + AOD = a.65° b. 180° c.110° d. 125°​

Answer 1

Step-by-step explanation:

We have :

∠AOC=∠BOD   [Vertically-Opposite Angles]∴∠AOC+∠BOD=130°⇒∠AOC+∠AOC=130°   [∵∠AOC=∠BOD]⇒2∠AOC=130°⇒∠AOC=65°

Now,

∠AOC+∠AOD=180°  [∵COD is a straight line] ⇒65°+∠AOD=180°⇒∠AOC=115°

Answer 2

Answer:

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