Question

. In the given figure suspended from ceiling of lift
pulley, spring balance and string are massless and
the lift is accelerating downward with acceleration
g/2, then find the reading of spring balance
​

Answer 1

Answer:

Fs=2(kx), The reading will be double of that original reading.

Here a=g/2

if Fs=kx Therefore, (ma)=kx==>m(g/2)=kx==>mg=2(kx)

since..Fs=2(kx).

Explanation:

Hope u get it...