Question

In the given figure,TA and TB are tangents to the circle with centre 'O'.If angle ATB=80°,then find the measure of angle ABT​

Answer 1

Answer:

Step-by-step explanation:

AS TA=TB(tangent drawn from the same point)

Means, Angle A=angle B(opposite angles will be equal)

Let angles to be X

So,

80+X+X=180

2X=100

X=50

Means Angle ABT=50°

HOPE YOU WILL GET IT

Answer 2

Answer:

The measure of ∠ABT is 50°

Step-by-step explanation:

Given TA and TB are tangents to the circle with centre 'O'. If ∠ATB=80° then we have to find the measure of ∠ABT​.

As, TA=TB (tangent drawn from the same point)

⇒ ∠TAB=∠TBA

Let it be x i.e ∠TAB=∠ABT=x

In ΔTAB, by angle sum property

∠ATB+∠TAB+∠ABT=180°

80+x+x=180

2x=100

x=50

∠TAB=∠ABT=x=50°

The measure of ∠ABT is 50°