In the given figure, tan xº= 3/4,
tan yº = 2/5 And angle theta =90°. If PQ=15cm, find MR
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tanx =PQ/mq =3/4
15/mq=3/4
mq=15*4/3=20
tany=PQ/rq =2/5
15/rq=2/5
rq=15*5/2 =37.5
Mr= rq-mq =37.5-20=17.5
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The answer is 17.5cm
GIVEN
tan xº= 3/4,
tan yº = 2/5 And angle theta =90°.
PQ = 15cm
TO FIND
The value of MR
SOLUTION
We can simply solve the above problem as follows;
In ΔPMQ
tan(x) = PQ/MQ
3/4 = 15/MQ
MQ = 15× (4/3) = 20cm
In ΔPQR
tan(y) = PQ/RQ
2/5 = 15/RQ
RQ = 15× (5/2) = 37.5cm
MR = RQ - MQ
MR = 17.5 cm
Hence, The answer is 17.5cm
#SPJ2
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