Question

In the given figure Tangent PT=16 PA= 8 find AB and PB ​

Answer 1

Step-by-step explanation:

In right angled ΔAMO

(AM)

2

+(OM)

2

=r

2

AB=5cm→AM=

2

5

cm. (M is midpoint if AB)

OM=

r

2

−

4

25

In right angled ΔPTO

(PT)

2

+(OT)

2

=(PO)

2

6

2

+r

2

=(PO)

2

PO=

r

2

+36

In right angled ΔPMO

(PM)

2

+(OM)

2

=(OP)

2

(PM)

2

+r

2

−

4

25

=r

2

+36

(PM)

2

=

4

169

PM=

2

13

PM=PA+AM

PA=PM−AM=

2

13

−

2

5

=4cm.