Question

in the given figure the area of shaded region is?​

Answer 1

lime CD is parallel to the line BA, so

∠BAD + ∠CDA = 180° { co-interior angles }

==> ∠BAD = 180° - 60° { given , ∠CDA = 60° }

==> ∠BAD = 120°

Now we need to the find the area of the shaded region ( or the sector PQ)

Given, radius of the sector = PA = 3 cm

We know,

$\sf \quad \boxed{ \sf Area \: of \: Sector = \pi {r}^{2} \frac{ \theta}{360} }$

So,

==> Area of shaded region = 22/7 × 3² × 120/360

take, π = 22/7

==> 22/7 × 9 × 1/3

==> 22/7 × 3

==> 66/7 cm²

Hence, area of the shaded region is 66/7 cm²

Answer 2

$\huge\mathtt{\underline{Answer}}$