Question

In the given figure the bisectors of angle A and angle B of a quadrilateral ABCD intersect at P.Prove that P is equidistant from AD and BC

Answer 1

Answer:

∵ P lies on the bisector of Angle B

∴ P is equidistant from AB and BC____(i)

∵ P lies on the bisector of Angle C

∴ P is equidistant from BC and CD____(ii)

From (i) and (ii)

P is equidistant from AD and BC.

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Step-by-step explanation: