In the given figure, the equation of AB is 2y-3x=6. Find the co ordinates of A and B.
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In the given figure, Let the point of which the coordinate is given as (4,0) be C
So,
⇒ ∠ACB = 90°
Since, The line segment BC is perpendicular to the x-axis, Therefore the Abscissa of point B would be 4 (Same as of C)
Now, We just need to find the ordinate of the point B to get the coordinate of the point.
But, The equation of line is given,
⇒ 2y - 3x = 6 [ given ]
Put, x = 4
⇒ 2y - 3×4 = 6
⇒ 2y = 18
⇒ y = 9
Hence, Coordinate of point B is (4,9)
Similarly, At point A it is clear that it is on the x-axis therefore the ordinate of this specific point is 0.
Using the equation of the line given in the question,
⇒ 2×0 - 3x = 6
⇒ -3x = 6
⇒ x = -2
Hence, Coordinate of point A is (-2,0)
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