Question

In the given figure, the
If ZBOD = x°, ZAOE =
son figure, the lines AB, CD and EF intersect at a point 0.
naro. ZAOE = 2xcº and ZCOF = 90°, find ZAOE and ZAOC. A
+
90°​

Answer 1

Answer:

ZCOF = ZEOD. ( Vertically opposite angles)

so ZEOD = 90°

ZAOE + ZEOD + ZDOB = 180°.( Angles on a straight line)

=> 2x + 90°+ x = 180°

=> 3x = 180-90

=> 3x = 90

=> x = 90÷3

=> x= 30°

so ZAOE = 2×30°=60°

ZCOF+ZAOC +ZAOE = 180° ( Angles on a straight line )

=> 90+ZAOC + 60=180

=> ZAOC + 150= 180

=> ZAOC =180-150=30°