Question

in the given figure the length of the lines AB and BC are in the ratio 2:3 .if angle AOB =80degree. find 1.angle BOC 2.angle ABC​

Answer 1

Answer:

∡AOB=96

0

AB

:

BC

=3:2

⇒∡AOB:∡BOC=3:2

⇒

∡BOC

96

0

=

2

3

⇒∡BOC=

3

2

×96

0

=64

0

Now, Δ

"

OBC is isosceles [∵ OB=OC=r]

∴ ∡BOC+2∡OBC=180

0

⇒∡OBC=

2

180−64

=58

0

also Δ

"

AOB is isosceles [because OA=OB=r]

∴ ∡AOB+2∡OBA=180

0

⇒∡OBA=

2

180−96

=42

0

∴ ∡ABC=58

0

+42

0

=100

0