Question

In the given figure, the line segment AB and CD bisects each other at a point 'P'. prove that triangle APC is congruent to triangle BPD

Answer 1

Hi friend,
In ΔAPC and ΔBPD
∠APC= ∠BPD(vertically opposite angles)
AP=BP(GIVEN)
CP=DP(GIVEN)
SO,ΔAPC ≈ ΔBPD (by SAS rule)
____________________________________________________Thanks :)___

Answer 2

Answer:

In ΔAPC and ΔBPD

∠APC= ∠BPD(vertically opposite angles)

AP=BP(GIVEN)

CP=DP(GIVEN)

SO,ΔAPC ≈ ΔBPD (by SAS rule)