Question

In the given figure, the mass of block A is 40 kgand of block B is 20 kg. There is no friction at anyof the contact surface. Both the systems are heldat rest initially. The ratio of acceleration of blockB in condition (i) to condition (ii) just at the momentsystem is released, is what?
|______ |________
| ( )````|'''''''''''| | ____ )|
| | | A. | | | A | |
| B|````| |____| | |____| |`''''| B

Answer 1

Step-by-step explanation:

correct answer is 3/2√2

Answer 2

Concept:

The acceleration is the rate of change of the velocity of an object with respect to time.

Mass is the quantity of the matter in a body.

Given:

We are given that :

the mass of block A is 40 kg and of block B is 20 kg.

Also, there is no friction.

Find:

We need to find the ratio of acceleration of block B.

Solution:

For condition 1:

20g-T=20a

a=20g/80

a=g/4

Now, the net acceleration is a₁=a√2:

So we get that:

√2 a=√2 g/4=g / (2√2).

For condition 2:

20g-T=20a

T=40a

a=g/3

a₂=g/3

a₁/a₂=(g / (2√2))/(g/3)=3/(2√2)

Therefore, the ratio of acceleration is 3:(2√2).

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