Question

In the given figure ,the measure of angle BAC is​

Answer 1

Step-by-step explanation:

Given:

In Δ$ABC$:

$AB=6 cm\\AC=BC=5cm$

∠$ABC=50^{o}$

∠$BAC=2x+20$

To find: ∠$BAC$

Calculation:

Since $AC=BC$, So the triangle is isosceles.

In an isosceles triangle, the opposite angles of equal sides are equal.

So, ∠$BAC=50^{o}$

Also,

∠$ABC=$∠$BAC$

$50^{o} =2x+20^{o} \\2x=30^{o} \\x=15^{o}$

Therefore, measure of ∠$BAC=2x+20=2*15+20=50^{o}$

Answer:

Measure of ∠$BAC$ is (b) $50^{o}$.