In the given figure, the measure of z is 10° less than twice the measure of y. If the difference of z and y is 20°, then the measure of (t + x) is equal to (z > y)
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90 aapka=9×10 =20nwjsjsb
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Given :
The measure of z is 10° less than twice the measure of y
The difference between z and y is 20°
To find:
The measure of (t+x)
Calculation :
=> z = 2y - 10 ...(1)
=> z - y = 20 ...(2)
From equations (1) and (2)
=> z - y = 20
=> 2y - 10 - y = 20
=> 3y - 10 = 20
=> y = 30°
=> z- y = 20°
=> z = 50°
Let the third angle in the triangle be c. We know that
Sum of angle in a triangle = 180°
=> c+z+y = 180°
=> c = 100°
From the figure it is clear that
=> c + 4x + 5t + c = 360°
=> 4x + 5t = 160°
=> 8x = 160° or 10t = 160° [4x an d5t are vertically opposite angles]
=> x = 20° or t = 16°
The sum of the angles x and t is
=> x+t = 20° + 16°
=> x+t = 36°
The measure of (t+x) is 36°
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