In the given figure, the natural length of spring is 0.4 m and spring constant is 200 N/m. The 3kg slider and attached spring are released from rest at end move in the vertical plane. The slider comes in rest at the point B. The work done by the friction during motion of slider is
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Answer:
bead of mass m can slide without friction on a fixed circular horizontal ring of radius 3R having centre at the point C. The bead is attached to one of the ends of spring of spring constant k. Natural length of spring is R and the other end of the spring is fixed at point O as shown in figure. Bead is released from position A, what will be kinetic energy of the bead when it reaches at point B?
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December 27, 2019avatar
Preethiga Sajeev
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ANSWER
Given,
mass of bead =m
radius of circular horizontal ring =3R
natural length of spring =R
According to conservation law of energy,
KE
i
+PE
i
=KE
f
+PE
f
⇒0+
2
1
k[OA−R]
2
=KE
f
+
2
1
k[OB−R]
2
⇒
2
1
−k[5R−R]
2
=KE
f
+
2
1
k[R−R]
2
⇒KE
f
=8kR
2
.
solution
December 27, 2019
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Toppr
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