Question

In the given figure the point 'P' bisects AB and DC. Prove that AAPC =~ ABPD
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Answer 1

Step-by-step explanation:

In given figure P bisect AB and DC

Then P is the mid point of AB and CD

Then AP=PB

And CP=PD

Then in ΔAPC and ΔBPD

AP=PB

CP=PD

∠APC=∠BPD..vertically opposite angles

∴ΔAPC≅ΔBPD