Question

In the given figure, the side BC is produced to the point D and E. Prove that <ABE+<ACD+<BAC=180​

Answer 1

Step-by-step explanation:

angle ABE can also be written as angle ABC

angle ACD can also be written as angle ACB

in triangle ABC

angle ABC + angle ACB + angle BAC = 180

so....

angle ABE + angle ACD + angle BAC = 180....