Math, asked by aditijha181, 14 hours ago

In the given figure, the side QR of ∆PQR is produced to

a point S. If the bisectors of <PQR and <PRS meet at

point T, then prove that

<QTR = ½<QPR​

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Answers

Answered by Triggerinsaan3535
0

Answer:

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Answered by shiza7
28

\mathfrak\red{ANSWER}

Given, Bisectors of PQR and ∠PRS meet

at point T.

To prove;

∠QTR= 1/2 QPR

PROOF-;

∠TRS=∠TQR+∠QTR (Exterior angle of a triangle equals to the sum of the two interior angles.)

⇒∠QTR=∠TRS−∠TQR --- (i)

Also ∠SRP=∠QPR+∠PQR

2∠TRS=∠QPR+2∠TQR

∠QPR=2∠TRS−2∠TQR

⇒ 1/2∠QPR=∠TRS−∠TQR ---(ii)

Equating (i) and (ii),

∴∠QTR= 1/2 ∠QPR

[hence proved]

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