in the given figure the side QR of triangle PQR is produced to the point S. If the bisectors of angle PQR and angle PRS meet at point T then prove that angle QTR =1/2 angle QPR.
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Step-by-step explanation:
in tringle PQR
PRS+PQR+QPR.........(exterior angle)
QPR=PRS_PQR......eqn1
in triangle QTR
TRS=QTR+TQR
QTR=TRS-TQR
1/2[PRS-1/2PQR]
1/2[PRS-PQR]
from eqn1...1/2QPR
this is your answer
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