Question

In the given figure, the sides AB and AC of ΔABC are produced to points E and D

respectively. If bisectors BO and CO of ∠ CBE and ∠ BCD respectively meet at point O, then

prove that ∠ BOC = 90° –




∠BAC .​

Answer 1

Answer:

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Answer 2

Refer The Attachment ⬆️

$\blue{\mathfrak{@MrMonarque}}$

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