In the given figure, the sides AB, BC and CA of a triangle ABC touch a
circle at P, Q and R respectively. If PA = 4 cm, BP = 3 cm and AC = 11
cm, find the length of BC (in cm). I want from 4 marks
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Answer:
hey mate here is the answer
Step-by-step explanation:
PA = 4 cm
BP = 3 cm
AB = 4+3= 7cm
AC= 11 cm
RA=PA= 4cm
RC = AC - RA
RC = 11-4= 7 cm
QC = RC = 7 cm
BP = BQ = 3 cm
BC = QC + BQ
BC = 7+3 = 10 cm is correct answer.
hope it's helpful to you.
Thank you.
other side name is S it is cut.
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