Question

In the given figure, the sides AB, BC and CA of triangle ABC, touch a circle at P, Q and R respectively. If PA = 4cm, BP= 3cm and AC = 11cm, then length of BC is-

Answer 1

Answer:

As given

PA=4cm

BP=3cm

∴AB=4+3=7cm

AC=11cm

As PA and RA is two tangents from same external point A

∴RA=PA=4cm

⇒RC=AC−RA

⇒RC=11−4=7cm

As RC and QC is two tangents from same external point C

∴QC=RC=7cm

As BP and BQ is two tangents from same external point B

∴BP=BQ=3cm

Then BC=QC+BQ

⇒BC=7+3=10cm

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