Question

in the given figure the sides BA and CA have been produced such that BA =AD and CA =AE . prove that DE ||BC​

Answer 1

Answer:

In ΔADE and ΔABC

BA = AD [ Given ]

CA=AE [ Given ]

∠1 = ∠ 2 [ Vertically opposite angles ]

ΔADE ≅ ΔABC [ SAS ]

∠ADE = ∠ABC [ cpct ]

∠ADE and ∠ABC are the alternate interior angles for the line segment DE and BC

Hence, using converse of alternate interior angle theorem,

DE || BC

this has been taught to us...so luckily an attachment was not required..

mark brainliest

Answer 2

$\huge\underline{\overline{\mid{\bold{\red{ANSWER-}}\mid}}}$

but <3 and <4 are also pair alternate interior angles, we know that when alternate interior angles are equal then the lines are said to be parallel