in the given figure the sides BA and CA have been produced such that BA = AD and CA = AE. Prove that DE||BC.
class 7 th math
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EA=AC [Given]
AD=AB [Given]
∠EAD=∠BAC [Vertically opposite angles]
So, by SAS congruence criterion, we obtain
ΔEAD≅ΔCAB
⇒∠AED=∠ACB and ∠ADE=∠ABC
⇒∠CED=∠ECB and ∠BDE=∠ABC
Hence, DE∥BC
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the answer is DE = BC
because DE & BC are opposite to each other
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