In the given figure, the value of x and y respectively is:
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Answered by
1
Answer:
In △TCE, we have
x=∠TCE+∠TEC (Exterior angle property)
⇒x=35
o
+31
o
⇒x=66
o
In △SBD , we have
∠AST=∠SBD+∠SDB
∠AST=30
o
+36
o
=66
o
In △ATS, we have
y+x+∠AST=180
o
(Angle sum property)
⇒y+66
o
+66
o
=180
o
⇒180
o
−(66
o
+66
o
)
⇒y=48
o
Answered by
1
Answer:
65 degree
Step-by-step explanation:
Lets Name the triangle ABC
Let the line perpendicular of BC be AD
Let the intersection point be E
<DEC= 180-90+20
= 180-110
= 70 degree
therefore <AFE= 70 degree (vertically oppsite angles are equal)
<x = 180-70+25
= 180-95
= 85 degree
<ADB=90 (Linear Pair)
therefore <y = 180- 25+90
= 180- 115
=65 degree
Hope you understood!
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