Question

in the given figure three blocks connected by string strings masses blocks are M 3 m and 5 cm respectively and they are pulled by the force f on a frictionless horizontal surface the tension f 1 in the first string is 16 Newton calculate acceleration of the blocks ,tension f2 in the 2nd string and force f​

Answer 1

Answer:

a; A= 2/m    m^2/s

b; F2 = 10N

c: F = 18 N

Explanation:

For all three parts, use Newton's second law, F = ma.

Finding the total acceleration;

The total mass of the system is

m = m1+m2+m3 = m  + 3m kg + 5m kg = 9m kg

As per given conditions;

F1= (m2+m3)x a;

16 = (8m)a

A= 16/8m

A= 2/m   m^2/s

(value of m has not been defined as per question statement)

Now ; calculating F2;

F2 = m3xa;

F2= 5m x 2/m;

F2 = 10N

Now calculating F;

Total force = m x a;

Mass have been calculated above;

F= 9m x 2/m;

F = 18 N

Answer 2

Answer:

a= 2/m m/s²,

Q = 10N,

F = 18N