In the given figure, three circles with centres A, B and C respectively touch each other externally. If AB = 15 cm, BC = 17 cm and CA = 16 cm, then find the radius of the circle with centre B.
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Answer:
8 cm
Step-by-step explanation:
Given, radius are equal
QB = PB
PA = RA
RC = QC
QC+QB =17
AP+PB = 15
AR+RC = 16
QC + QB = 15
AP + QB = 17
- - = -
QC - AP = -2
RA - QC = -2
RA + RC = 16
- - = -
-QC - RC = -18 :- QC = RC
2QC = 18
QC = 9
QC + QB = 17
9 + QB = 17
QB = 8 cm radius with center B.
QB = PB = 8 cm
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