Question

In the given figure three line AB,CD and EF intersecting O. Find the values of x,y and z it is being given that x:y:z=2:3:5

Answer 1

Answer:

x = 36

y = 54

z = 90

Step-by-step explanation:

= <DOB = Z

= <ADE = X

= <COF = Y

∴ x + x + y + y + z + z = 360

= 2(x + y + z) = 360

= x + y + z = 180 - - - (2)

= x : y : z = 2 : 3 : 5

= x = 2k, y = 3k, z = 5k - - (1)

= [SUBSTITUTING] (1) and (2); we get

= 2k + 3k + 4k = 180

= 10k = 180

= k = 18

∴ x = 36

  y = 54

  z = 90

Answer 2

Step-by-step explanation:

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