Math, asked by lovenj, 1 year ago

in the given figure three lines AB,CD and EF intersecting at O. Find the values of x,yand z it is being given that x:y:z=2:3:5

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Answered by ashk02
6
In figure
angle DOB= z
angle AOE= x
angle COF= y

therefore x+x+y+y+z+z=360°
2(x+y+z)=360
x+y+z=180____________(2)

x:y:z= 2:3:5
x= 2k , y= 3k , z= 5k _____(1)
substituting(1) in (2)
2k+3k+5k=180
10k=180
k=18

therefore
x=2×18=36°
y=3×18=54°
z=5×18=90°
_____________________________
hope this helps you
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Answered by Anonymous
2

Answer:

In figure

angle DOB= z

angle AOE= x

angle COF= y

therefore x+x+y+y+z+z=360°

2(x+y+z)=360

x+y+z=180____________(2)

x:y:z= 2:3:5

x= 2k , y= 3k , z= 5k _____(1)

substituting(1) in (2)

2k+3k+5k=180

10k=180

k=18

therefore

x=2×18=36°

y=3×18=54°

z=5×18=90°

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