in the given figure three lines AB,CD and EF intersecting at O. Find the values of x,yand z it is being given that x:y:z=2:3:5
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In figure
angle DOB= z
angle AOE= x
angle COF= y
therefore x+x+y+y+z+z=360°
2(x+y+z)=360
x+y+z=180____________(2)
x:y:z= 2:3:5
x= 2k , y= 3k , z= 5k _____(1)
substituting(1) in (2)
2k+3k+5k=180
10k=180
k=18
therefore
x=2×18=36°
y=3×18=54°
z=5×18=90°
_____________________________
hope this helps you
please do mark as brainliest
angle DOB= z
angle AOE= x
angle COF= y
therefore x+x+y+y+z+z=360°
2(x+y+z)=360
x+y+z=180____________(2)
x:y:z= 2:3:5
x= 2k , y= 3k , z= 5k _____(1)
substituting(1) in (2)
2k+3k+5k=180
10k=180
k=18
therefore
x=2×18=36°
y=3×18=54°
z=5×18=90°
_____________________________
hope this helps you
please do mark as brainliest
Answered by
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Answer:
In figure
angle DOB= z
angle AOE= x
angle COF= y
therefore x+x+y+y+z+z=360°
2(x+y+z)=360
x+y+z=180____________(2)
x:y:z= 2:3:5
x= 2k , y= 3k , z= 5k _____(1)
substituting(1) in (2)
2k+3k+5k=180
10k=180
k=18
therefore
x=2×18=36°
y=3×18=54°
z=5×18=90°
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