In the given figure three lines AB,CD and EF intersecting at o . find the values of x,y,and z it is being given that x:y:z =2:3:5
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is the figure a triangle or what???
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Given x:y:z=2:3:5
let x=2a,y=3a,z=5a
angle BOF=angle AOE(vertically opposite angles)
angle EOD =angle COF (vertically opposite angle)
angle AOC=angle DOB(vertically opposite angle)
we know that sum of all the angles at a point is 360
2a+3a+5a=360
10a=360
a=360/10=36
a=36
therefore, 2a =2*36=72
3a=3*36=108
5a=5*36=280
let x=2a,y=3a,z=5a
angle BOF=angle AOE(vertically opposite angles)
angle EOD =angle COF (vertically opposite angle)
angle AOC=angle DOB(vertically opposite angle)
we know that sum of all the angles at a point is 360
2a+3a+5a=360
10a=360
a=360/10=36
a=36
therefore, 2a =2*36=72
3a=3*36=108
5a=5*36=280
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