In the given figure, three tangents TP, TQ and
AB are respectively drawn at the points P, Q and
R to a circle. Find the semi-perimeter of ATAB,
if length of TP is 13 cm.
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Answer:
semi perimeter of ΔTAB= 13cm
Step-by-step explanation:
1/2(TA+AB+TB)
TQ=TB+BQ-1
TQ= TB+RB-2
Add 1 and 2
TA+AR+TB+BR
TA+AR=13
TB+BR=13
13+13=26
semi perimeter of ΔTAB
1/2*26=13cm
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Step-by-step explanation:
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