Math, asked by Virtualpaint, 6 hours ago

In the given figure, TP and TQ are tangents to the circle with centre O such that POQ = 100°, then find PTQ?

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Answered by shetalvora

1

Answer:

ptq = 360 -(90+90+100) = 360-280 = 80 degrees (Angle sum property of quadrilateral, Tangent properties)

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