Question

in the given figure traingleODC~traingleOAB,BOC=100 traingle ODC 60 then
FIND traingle OAB is equal to​

Answer 1

Answer:

ZDOC + 125º = 180° (linear pair)

+ ZDOC = 180° 125° = 55°

In ADOC

SEDCO + DO + ZDOC = 180° (sum of

three angles of AODC)

ZDCO + 70° +55º = 180°

+ ZDCO + 125° = 180°

> ZADCO = 180° – 125° = 55°

Now we are given that AODC~AOBA

→ ZOCD = ZOAB (Corresponding angles

of similar triangles)

+ ZOOM = ZOCD = ZADCO = 55°

i.e., ZOAB = 55°

Hence we have,

ZDOC = 55°; ZDCO = 55°; ZOAB = 55°