In the given figure: triangle ABC =ADC . If angle BAC=35^ & angle ABC=95^ . Then, find the measure of angle ACD
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∠DCE=∠EAB (Alternate angles as AB∣∣DE and AE is transversal)
∠DEC=35
∘
In △DCE, we have
∠DCE+∠CED+∠CED=180
∘
(Angle sum property)
∠DCE+35
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+53
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=180
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∠DCE=180
∘
−88
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=92
∘
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