Question

In the given figure triangle ABC and DCB are right angled at A and D respectively and AB= DC . Prove that angel ABC= ANGEL DCB

Answer 1

in tringle ABC and tringle BCD
AB=CD (given)
cone BAC= coneACD (AB is parallel with DC and AC divider)
coneABD= cone BDC
so according to the law of A-A-S
this to tringles are fully identical

Answer 2

Given, ∆ABC and ∆DCB are right angled at A and D.
AB = DC
To prove : ∆ ABC congruent ∆DBC
Proof
In ∆ABC and ∆DBC
AB = CD ( given )
BC = BC. ( Common)
Therefore, by RHS criteria
∆ABC congruent ∆DBC
By cpct Hence proved