Question

In the given figure, triangle ABC and triangle DBC are two isosceles triangles on the same base BC. Prove
that AP is perpendicular bisector of BC.​

Answer 1

Step-by-step explanation:

Given: ∆ABC and ∆DBC are two isosceles triangles on the same base BC and vertices A and D are on the same side of BC. AD is extended to intersect BC at P. (iv) AP is the perpendicular bisector of BC. ∴ ∠BAP = ∠CAP ...

Given: ∆ABC and ∆DBC are two isosceles triangles on the same base BC and vertices A and D are on the same side of BC. AD is extended to intersect BC at P. (iv) AP is the perpendicular bisector of BC. ∴ ∠BAP = ∠CAP ...

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