Question

In the given figure, triangle ABC and triangle DCB are on same base BC. If AD and BC intersects at O prove that ar(triangle ABC) /ar(triangle DBC) =AO/DO

Answer 1

Answer:

Step-by-step explanation:

Triangle ABC and Triangle DBC have common base ... (given)

I. E. BC

Let us take seg BC as x.

Therefore, ar ( triangle ABC) / ar ( triangle DBC) = B1*H1/B2*H2

Therefore, ar ( triangle ABC) / ar (

triangle DBC) = x* AO/x* DO

x gets cancelled from numerator and denominator

Hence proved.