Question

. In the given figure, triangle ABC is an isosceles
triangle with AB = AC. If the measure of
exterior angle, angleEBC=110°, find the measures
of angle BCD and angle A.​

Answer 1

Answer:

Step-by-step explanation:

AB=AC Given

∠ABC=180-∠EBC    (LINEAR PAIR)

         =180-110=70

∠ABC=∠ACB     (ANGLES OPPOSITE TO EQUAL SIDES ARE EQUAL)

∠ACB=70

∠DCB+∠ACB=180

∠DCB=180-∠ACB

          =180-70

  ∠BCD=110

∠A+∠BCA=110  (EXTERIOR ANGLE PROPERTY)

∠A=110-70

∠A=40