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In the given figure, triangle ABC is equilateral .Find angle BEC fastttt
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It is given that △ ABC is equilateral
We know that
∠BAC = ∠ABC = ∠ACB = 60°
(i) We know that the angles in the same segment of a circle are equal
∠BDC = ∠BAC = 60°
So we get
∠BDC = 60°
(ii) We know that the opposite angles of a cyclic quadrilateral are supplementary
So we get
∠BAC + ∠BEC = 180°
By substituting the values
60° + ∠BEC = 180°
On further calculation
∠BEC = 180° – 60°
By subtraction
∠BEC = 120°
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