Question

in the given figure triangle ABC is right angled at C and CD perpendicular AB. If angle A = 50°, find angle ACD, ABC, BCD. ​

Answer 1

Answer:

1. Angle ACD=40 degree
2. Angle ABC=50 degree
3. Angle BCD=40 Degree..

Answer 2

Answer:

ABC=50°

ACD=80°

BCD=40°

Step-by-step explanation:

ABC=50°

CAD=CBD

50°=CBD

50°=50°

ACD=80°

180°-(CAD+CDA)

180°-(50°+90°)=40°

40°+40°=80°

BCD=40°

180°-(CBD+CDB)

180°-(50°+90°)=40°

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