In the given figure triangle ABC is right angled at C . Find x
Attachments:
Answers
Answered by
0
Given D is the midpoint of BC.
DC=1/2BC
ABC is a right triangle.
AB
2
=AC
2
+BC
2
…(i)[Pythagoras theorem]
ADC is a right triangle.
AD
2
=AC
2
+DC
2
…(ii)[Pythagoras theorem]
AC
2
=AD
2
−DC
2
AC
2
=AD
2
–(1/2BC)
2
[∵DC=1/2BC]
AC
2
=AD
2
–1/4BC
2
4AC
2
=4AD
2
–BC
2
AC
2
+3AC
2
=4AD
2
–BC
2
AC
2
+BC
2
=4AD
2
−3AC
2
AB
2
=4AD
2
−3AC
2
[from (i)]
Similar questions