Question

In the given figure triangle ABC is similar to triangle ADE then find the value of

Answer 1

Answer:

BC = 10 cm

Step-by-step explanation:

if triangle ABC is similar to triangle ADC

then,  $\frac{AE}{EC} =\frac{DE}{BC}$     (c.p.s.t.)

   =   $\frac{3}{6}= \frac{5}{BC}$

  =BC = $\frac{5(6)}{3}$  ⇒    10cm

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