Question

in the given figure triangle ABC is similar triangle EDC.If lengths of AB,ED,CE,CD(in centimeters) are 5,2,2.4,2.2 respectively,then the lengths of CA and CB respectively(in centimeters) are

Answer 1

Answer:

AB/ED=AC/EC=BC/DC

5/2=AC/2,4=BC/2.2

AC=6

BC=5.5

Step-by-step explanation:

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Answer 2

The length of CA is 6cm and the length of BC is 5.5cm

GIVEN

ABC is similar triangle EDC.If lengths of AB,ED,CE,CD(in centimeters) are 5,2,2.4,2.2 respectively.

TO FIND

The lengths of CA and CB respectively(in centimeters) are.

SOLUTION

We can simply solve the above problem as follows;

We know that,

ΔABC ≈ ΔEDC

Since the two triangles are similar then the corresponding sides of the two triangles are proportional to each other.

Therefore,

$\frac{ab}{de} = \frac{bc}{dc} = \frac{ac}{ec}$

Putting the values in the above equation

$\frac{5}{2} = \frac{bc}{2.2} = \frac{ac}{2.4}$

Cross multiplying,

BC = (2.2×5)/2 = 5.5 cm

AC = (5.5×2.4)/2.2 = 6cm

Hence, The length of CA is 6cm and the length of BC is 5.5cm

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