Question

In the given figure,triangle ACB is a right angled triangle at C and CD | AB. If angleB = 40°, then find :
¡]angleBAC
¡¡]angleACD
¡¡¡]angleBCD





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Answer 1

Answer:

angle BAC =50°

angle ACD=40°

angle BCD=50°

Answer 2

Answer:

Step-by-step explanation:

In triangle ABC

Ang. Bac + ang. Acb + ang. ABC = 180 ° ....... angle sum property of triangle

Ang .Bac +40°+90°=180°

Ang.Bac =180°-130° = 50°

In triangle BCD

Ang . CDB + Ang . DBC + Ang . DCB =180 ......angle sum property of triangle

90 ° + 40° + Ang. BCD =180

Ang . BCD =180°- 130 ° = 50 °

Ang .ACD + BCD =90°

Ang ACD + 50 ° = 90 °

Ang. ACD = 90°-50°

= 40 °